Respuesta :
we are given the equation 3y^2-5x^2=7 and 3y^2-x^2=23. there are two equations two unknowns hence the problem can be solved.
3y^2-5x^2=7
3y^2 =x^2 + 23
x^2 + 23 = 7 + 5x^2
4x^2 = 16
x^2 = 4
x1 =2
x2 = -2
sum is 2-2 = 0
3y^2-5x^2=7
3y^2 =x^2 + 23
x^2 + 23 = 7 + 5x^2
4x^2 = 16
x^2 = 4
x1 =2
x2 = -2
sum is 2-2 = 0
Answer:
The sum of the x coordinates is 0.
Step-by-step explanation:
3y^2-5x^2=7
3y^2 =x^2 + 23
-4x^2 = -16
x^2 = 4
x= -2, 2
2-2=0