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antonsandiego
It's not enough details to solve this task but I think I've got it right. Size of OAB = AOC then ABC is D. 35.
calculista

Answer:

Option D

m∠ABC=[tex]35\°[/tex]

Step-by-step explanation:

we know that

The inscribed angle measures half that of the arc comprising

In this problem

m∠ABC is the inscribed angle

so

m∠ABC=[tex]\frac{1}{2}(arc\ AC)[/tex]

[tex]arc\ AC=70\°[/tex] -------> by central angle

substitute

m∠ABC=[tex]\frac{1}{2}(70\°)=35\°[/tex]

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