Respuesta :

[tex]C(8,3)=\dfrac{8!}{3!5!}=\dfrac{6\cdot7\cdot8}{2\cdot3}=7\cdot8=56[/tex]

The evaluated value of C(8,3) is "56"

Evaluation:

[tex]\to \bold{C(8,3)}[/tex]

Using formula:

[tex]\bold{^nC_r=\frac{n!}{n!(n-r)!}}[/tex]

[tex]\to {^8C_3=\frac{8!}{3!(8-3)!}}\\\\[/tex]

          [tex]=\frac{8!}{3!(5)!}\\\\=\frac{8 \times 7 \times 6 \times 5!}{3!\times 5!}\\\\=\frac{8 \times 7 \times 6 \times 5!}{3\times 2 \times 1 \times 5!}\\\\={8 \times 7}{}\\\\=56\\[/tex]

Therefore, the final answer is "56".

Find out more information about the Combination here:

https://brainly.com/question/24442374