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A 150 mL sample of hydrochloric acid (HCl) completely reacted with 60.0 mL of a 0.100 M NaOH solution. The equation for the reaction is given below. HCl + NaOH mc011-1.jpg NaCl + H2O. What was the original concentration of the HCl solution?

Respuesta :

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The balanced chemical reaction is expressed as:

HCl + NaOH ---> NaCl + H2O

We are given the amount and the concentration of the sodium hydroxide reactant. This will be the starting point for the calculations. 

0.100 mol NaOH/L solution (0.06 L solution) ( 1 mol HCl / 1 mol NaOH) = 0.006 mol HCl

Molarity = amount in moles / Volume of solution = 0.006 mol HCl/ 0.150 L
Molarity = 0.04 M
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The original concentration of the HCl solution is 0.04 M.

What is molality?

Molality is the measure of the moles of any solute in a solution per unit kg of the solvent.

[tex]\rm HCl + NaOH --- > NaCl + H^2O[/tex]

[tex]\rm Molality = \dfrac{mol}{kg}\\\\\rm Molality = \dfrac{0.006 mol HCl}{0.150 L} = 0.04 M[/tex]

Thus, the original concentration of the HCl solution is 0.04 M.

Learn more about molality

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