The electrolyte in automobile lead storage batteries is a 3.75 M sulfuric acid solution that has a density of 1.230 g/mL. Calculate the mass percent, molality, and mol fraction of the sulfuric acid.

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throwdolbeau throwdolbeau · Answer 1 · 2022-04-02T10:01:37+02:00

The mass percentage = 20.7 %

The molality = 3.85 m

Molarity is defined as the ratio of the number of moles over the Volume of solution.

Molarity= moles of solute/L of solution

Molality=moles of solute/kg of solvent

Let's assume you have 3.75mol sulfuric acid in 1L of the solution, which would give us 3.75M

3.75 mol * 68.03 g (molecular weight)= 255 grams.

1L * 1000 mL/1L= 1000mL solution

So,

Density=mass/volume.

On subsituting the values:

1.23 g/mL = mass/1000mL

1.23g/mL * 1000mL=1230 grams solution.

So, Mass percent= (255 grams H₂SO₄/1230 grams solution)*100%

Mass percent=20.7%

Calculation of molality:

Molality = moles of solute/kg of solvent

255g + Solvent = 1230g

Solvent=1230g-255g

We have 3.75 mol H₂SO₄ and .975 kg Solvent.

Thus, the molality of the solution is:

Mol solute/kg solvent= 3.75 mol/.975 kg= 3.85m

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