Respuesta :
Answer:
34601 liters
Step-by-step explanation:
Given:
Ben is filling his cylinder shaped pool up to 80% of its capacity.
His pool is 6 feet deep and has a diameter of 18 feet.
Question asked:
How much water will he put in the pool?
Solution:
First of all we will find volume of cylinder:
Diameter = 18 feet
Radius, r = [tex]\frac{Diameter}{2} =\frac{18}{2} =9\ feet[/tex]
Height, h = 6 feet
As we know:
[tex]Volume\ of \ cylinder=\pi r^{2} h[/tex]
[tex]=\frac{22}{7} \times(9)^{2} \times 6\\ \\=\frac{22}{7} \times81 \times 6\\ \\ =\frac{10692}{7} \\ \\ =1527.42\ cubic\ feet[/tex]
Now, as given that pool is being filled up to 80%, we have to find quantity of water he will put in the pool:-
Quantity of water filled = 80% of the volume of the pool
[tex]=\frac{80}{100} \times1527.42\\ \\ =1221.93\ cubic feet[/tex]
Now, convert it into liters.
1 cubic feet = 28.31 liters
1221.93 cubic feet = 28.31 [tex]\times[/tex] 1221.93 = 34,601.20 liters
Therefore, he will put about 34601 liters water in the pool.
