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suppose a penny-farthing bicycle has a front wheel with a diameter of 5ft. To the nearest tenth of a foot, how far does the bike move when you turn the pedals through an angle of 90 degrees?

Respuesta :

Answer:

3.9 ft.

Step-by-step explanation:

Hope this helped!

The bike is 3.9 feet far does the bike move when you turn the pedals at an angle of 90 degrees.

What is the circumference of the circle?

The Circumference (or) perimeter of the circle = 2πR. where R is the radius of the circle.

The radius of the circle is;

[tex]\rm Radius=\dfrac{Diameter}{2}\\\\Radius=\dfrac{5}{2}\\\\Radius=2.5[/tex]

The bike move when you turn the pedals at an angle of 90 degrees is;

[tex]= \dfrac{90}{360} \times 2 \times 3.14 \times 2.5\\\\= \dfrac{1}{4} \times 2 \times 3.14 \times 2.5\\\\=3.9\\\\[/tex]

Hence. the bike is 3.9 feet far does the bike move when you turn the pedals at an angle of 90 degrees.

Learn more about circumference here;

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