Lance is building a rectangular fence for his chickens. He wants the length to be three times the width and he has 80 feet of fencing. What is the largest possible length? Write an equation and solve.

A) 8w=80; 10
B) 4w=80; 20
C) 8w=80; 30
D) 4w=80; 15

Respuesta :

Answer:

A) 8w=80; 10

Step-by-step explanation:

Let w = width

L = 3w

Fencing is perimeter

P=2(l+w)

80 = 2(3w+w)

80 = 2(4w)

80 = 8w

Divide each side by 8

80/8 = 8w/8

10 = w

The equation would be '8w = 80; 10'

As per the question,

Assume the width of the rectangular fence to be w. So,

Length(l) = 3w

Total fencing he has = 80 meters.

As we know,

Fencing denotes the perimeter and the building is rectangular. Thus,

[tex]Perimeter = 2 (l + b)[/tex]

Since b here is denoted by w, the equation would be after substituting the above values;

[tex]80 = 2(3w + w)[/tex]

⇒ [tex]80 = 2(4w)[/tex]

⇒ [tex]80 = 8w[/tex]

∵  [tex]w = 80/8 = 10[/tex]

Thus,

The largest possible length = [tex]10[/tex] × [tex]3 = 30 feet[/tex]

Breadth(w) as we get = [tex]10 feet[/tex]

Thus, option A is the correct answer.

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