The loudness level of a​ sound, D, in​ decibels, is given by the formula Upper D equals 10 log (10 Superscript 12 Baseline Upper I )D=10log1012I​, where I is the intensity of the​ sound, in watts per metersquared2. Decibel levels range from​ 0, a barely audible​ sound, to​ 160, a sound resulting in a ruptured eardrum. The sound of a certain animal can be heard 500 miles​ away, reaching an intensity of 2.62.6times×10 Superscript 6106 watts per meter squared .meter2. Determine the decibel level of this sound. At close​ range, can the sound of this animal rupture the human​ eardrum?

Respuesta :

complete question

attached

Answer:

188.0 decibels

Explanation:

Substitute I = 6.3 x 10^6 into the given formula  

D(6.3 x 10^6) = 10log(10^12 x 6.3 x 10^6) = 188.0 to one decimal place.  

This is greater than 160 decibels, so the sound could rupture the human eardrum.  

Substitute I = 6.3 x 10^6 into the given formula  

Ver imagen Hashirriaz830