Answer:
[tex]\dot W_{out} = 399.47\,kW[/tex]
Explanation:
The turbine is modelled after the First Law of Thermodynamics:
[tex]-\dot Q_{out} -\dot W_{out} + \dot m\cdot (h_{in}-h_{out}) = 0[/tex]
The work done by the turbine is:
[tex]\dot W_{out} = \dot m \cdot (h_{in}-h_{out})-\dot Q_{out}[/tex]
The properties of the water are obtained from property tables:
Inlet (Superheated Steam)
[tex]P = 10\,MPa[/tex]
[tex]T = 520\,^{\textdegree}C[/tex]
[tex]h = 3425.9\,\frac{kJ}{kg}[/tex]
Outlet (Superheated Steam)
[tex]P = 1\,MPa[/tex]
[tex]T = 280\,^{\textdegree}C[/tex]
[tex]h = 3008.2\,\frac{kJ}{kg}[/tex]
The work output is:
[tex]\dot W_{out} = \left(1.1\,\frac{kg}{s}\right)\cdot \left(3425.9\,\frac{kJ}{kg} -3008.2\,\frac{kJ}{kg}\right) - 60\,kW[/tex]
[tex]\dot W_{out} = 399.47\,kW[/tex]
