749.69 ml is the new volume if, with the pressure and amount of gas held constant the temperature is decreased to 253 K.
Explanation:
Data given:
Initial volume of the neon gas V1 = 886 ml
initial pressure of the neon gas P1 = 752 torr or
initial temperature of the neon gas T1 = 299 K
Final volume =?
pressure constant so final pressure = initial pressure hence P2 = P1
fInal temperature of the neon gas T2 = 253 K
applying the Gay Lussac equation
[tex]\frac{P1V1}{T1}[/tex] = [tex]\frac{P2V2}{T2}[/tex]
Pressure can be removed from the equation as it is constant, so we apply Charles' Law equation:
[tex]\frac{V1}{T1}[/tex] = [tex]\frac{V2}{T2}[/tex]
rearranging the above equation to know final volume:
V2= [tex]\frac{V1T2}{T1}[/tex]
V2 = [tex]\frac{886 X253 }{299}[/tex]
V2 = 749.69 ml
final volume is 749.69 ml
