Respuesta :
Answer:
a) the Angle te also decreases , b) decrease, c) unchanged , d) the speed decrease , e) unchanged
Explanation:
When a ray of light passes from one transparent material to another, it must comply with the law of refraction
n1 sin θ₁ = n2 sin θ₂
Where index v1 is for the incident ray and index 2 for the refracted ray
With this expression let's examine the questions
a) They indicate that the refractive index increases,
sin θ₂ = n₁ / n₂ sin θ₁
θ₂ = sin⁻¹ (n₁ /n₂ sin θ₁)
As m is greater than n1 the quantity on the right is less than one, the whole quantity in parentheses decreases so the Angle te also decreases
Answer is decrease
b) The wave velocity eta related to the wavelength and frequency
v = λ f
The frequency does not change since the passage from one medium to the other is a process of forced oscillation, resonance whereby the frequency in the two mediums is the same.
The speed decreases with the indicated refraction increases and therefore the wavelength decreases
λ = λ₀ / n
The answer is decrease
c) from the previous analysis the frequency remains unchanged
d) the refractive index is defined by
n = c / v
So if n increases, the speed must decrease
The answer is decrease
e) the energy of the photon is given by the Planck equation
E = h f
Since the frequency does not change, the energy does not change either
Answer remains unchanged
a) The Angle te also decreases, b) Decrease, c) Unchanged, d) The speed decrease, e) Unchanged
What is the Law of Refraction?
When a glimmer of light perishes from one translucent material to another, it must capitulate with the law of refraction
n1 sin θ₁ = n2 sin θ₂
Where index v1 is for the happening ray and index 2 is for the refracted ray With this expression let's discuss.
a) They indicate that the refractive index increases,
sin θ₂ = n₁ / n₂ sin θ₁
θ₂ = sin⁻¹ (n₁ /n₂ sin θ₁)
As m is more significant than n1 the quantity on the ownership is less than one, the whole quantity in parentheses diminishes so the Angle te also decreases
Solution is decrease
b) The wave velocity eta connected to the wavelength and frequency
v = λ f
The frequency does not modify since the passage from one medium to the other is a procedure of forced oscillation and resonance whereby the frequency in the two mediums is the same.
The speed decreases with the foreshadowed refraction increases and thus the wavelength decreases
So, λ = λ₀ / n
The answer is to decrease
c) from the earlier analysis the frequency remains unchanged
d) When the refractive index is defined by
n is = c / v
Then, if n increases, the speed must decrease
The solution is to decrease
e) When the energy of the photon is given by the Planck equation
E is = hf. Since When the frequency does not transform, the energy does not change either Solution is remains unchanged
Find more information about Law of Refraction here:
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