Respuesta :
Answer:
Frequency, f = 59.6 kHz
Explanation:
Given that,
Speed of sound, v = 340 m/s
The bat can detect an insect that is 0.0057 m long, [tex]\lambda=0.0057\ m[/tex]
We need to find the minimum frequency of sound waves required for a bat to detect an insect. The speed of a wave is given by :
[tex]v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{340\ m/s}{0.0057\ m}\\\\f=59649.12\ Hz[/tex]
or
f = 59.6 kHz
So, the frequency detected by the bat is 59.6 kHz.
The minimum required frequency of the sound wave is 59.65 kHz
Determining frequency:
Given information:
speed of sound, v = 340 m/s
the wavelength of insect that the bat can detect, λ = 0.0057 m
The wavelength, frequency, and speed are related as follows:
v = fλ
The minimum frequency of sound wave required is:
f = v/λ
where f is the frequency of the sound
f = 340/0.0057 s⁻¹
f = 59649 Hz
or,
f = 59.65 kHz
So the frequency comes out to be 59.65 kHz
Learn more about frequency:
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