Answer:
[tex]\frac{\delta B}{\delta t}= 0.0995 \ T/s[/tex]
Explanation:
Given that :
The radius of the circular loop = 4.0 m
Maximum Emf [tex]E_{max}[/tex] = 5.0 V
The maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies can be determined via the expression;
[tex]E_{max}[/tex] = [tex]Area (A) * \frac{\delta B}{\delta t}[/tex]
[tex]E_{max}[/tex] = [tex]\pi r^2 * \frac{\delta B}{\delta t}[/tex]
5.0 = [tex]\pi * (4.0)^2 * \frac{\delta B}{\delta t}[/tex]
5.0 = [tex]50.27 * \frac{\delta B}{\delta t}[/tex]
[tex]\frac{\delta B}{\delta t}= \frac{5}{50.27}[/tex]
[tex]\frac{\delta B}{\delta t}= 0.0995 \ T/s[/tex]
