A clothing store is having a sale on shirts and jeans.Five shirts and 3 pairs jeans cost $220. Six shirts and 2 pairs of jeans cost $200. How much is the cost of one shirt? How much is the cost of pair of jeans?

Respuesta :

Answer:

Shirt: $20

Trouser: $40

Step-by-step explanation:

5x + 3y = 220

6x + 2y = 200

3x + y = 100

y = 100 - 3x

5x + 3(100 - 3x) = 220

5x + 300 - 9x = 220

4x = 80

x = 20

y = 100 - 3(20)

y = 40

The cost of a shirt is $20 and the cost of pair of a jeans is $40.

Given that, five shirts and 3 pairs of jeans cost $220. Six shirts and 2 pairs of jeans cost $200.

We need to find the cost of one shirt and the cost of pair of jeans.

What is a linear equation?

A linear equation is an equation in which the highest power of the variable is always 1.

A linear equation in two variables is of the form Ax + By + C = 0, in which A, B, and C are real numbers and x and y are the two variables, each with a degree of 1. If we consider two such linear equations, they are called simultaneous linear equations.

Let the cost of a shirt be x and the cost of pair of jeans be y.

Now, five shirts and 3 pairs of jeans cost $220.

That is, 5x+3y=220------(1)

Six shirts and 2 pairs of jeans cost $200.

6x+2y=200------(2)

Multiplying the equation (1) with 2, we get 10x+6y=440------(3)

Multiplying the equation (2) with 3, we get 18x+6y=600------(4)

Now, equation (4)-(3) is 8x=160

⇒x=$20

Substitute x=20 in equation (1), we get 5(20)+3y=220

⇒y=$40

Therefore, the cost of a shirt is $20 and the cost of pair of a jeans is $40.

To learn more about the linear equation visit:

https://brainly.com/question/27664510.

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