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Proving the Parallelogram Diagonal Theorem
Given: ABCD is a parallelogram.
Diagonals AC, BD intersect at E.
Prove: AE CE and BE DE
Statements
✓ 1. ABCD is a parallelogram
Reasons
1. given
Correctl Assemble the next
statement.
) Intro

Respuesta :

AECD is a parallelogram but I don’t get it

From the given parameters with reasons and statements, we have proven that AE = CE and BE = DE from; Properties of Parallelogram and ASA Congruence Postulate.

How to do a two - column proof?

Statement 1; ABCD is a parallelogram

Reasons 1; given

Statement 2; ∠ABE and ∠CDE are alternate Interior angles

Reason 2; Definition of Alternate Interior angles

Statement 3; ∠BAE and ∠DCE are alternate Interior angles

Reason 3; Definition of Alternate Interior angles

Statement 4; AB = CD

Reason 4; Parallelogram side theorem

We want to prove that AE = CE and BE = DE

From properties of parallelogram, we can say that ∠CBD = ∠ABD and also ∠BCA = ∠DAC

Thus, it means that; ΔBEC ≅ ΔAED

Thus, from ASA Congruency postulate, we can say that;

AE ≅ CE and BE ≅ ED

Read more about two column proof at; https://brainly.com/question/1788884

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