Answer:
1.6 ×[tex]10^{-7}[/tex]M
Explanation:
[tex]K_{sp}[/tex] for calcium diphosphate is 8.64x10^(-13)
concentration of the calcium cations = 2.2955 x 10^−3M
[tex]Ca_{2}P_{2} O_{7}_(s)[/tex] ⇄[tex]2Ca_{2}_(aq)[/tex] + [tex]P_{2}O^{4-} _{7}_(aq)[/tex]
[tex]K_{sp}[/tex] = [tex][Ca^{2+}]^{2}[/tex]×[tex][P_{2} O^{4-}_7][/tex]
converting the concentration of the calcium cations from 9.2mg/dL to moles per liter , we get 2.2955 x [tex]10^{-3}[/tex]M
[tex][P_{2} O^{4-}_7][/tex] = [tex]\frac{K_{sp} }{[Ca^{2+}]^{2} }[/tex]
[tex][P_{2} O^{4-}_7][/tex] = [tex]\frac{8.64 . 10^{-13} }{[2.2955 . 10^{-3}]^{2} }[/tex]
=1.6 ×[tex]10^{-7}[/tex]M
