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Oh freight elevator can hold a maximum weight of 3500 pounds and delivery man weighs 200 pounds is delivering curtains that each way 48 pounds he wants to know how many current you can safely put on the elevator at one time let's see represent the number of cartons write an inequality that represents the situation

Respuesta :

Answer:

[tex]200+48n\leq 3500[/tex]

[tex]n\leq 66.7[/tex]

Step-by-step explanation:

  • The freight elevator can hold a maximum weight of 3500 pounds
  • The delivery man weighs 200 pounds
  • Each carton weighs 48 pounds

Let the number of cartons he can safely put on the elevator at one time=n

Total weight of Carton=48n

Since the weight of the man and the cartons combined must not be more than 3500 pounds,

Therefore,an inequality that represents the situation is:

[tex]200+48n\leq 3500[/tex]

We can solve for n if required

[tex]200-200+48n\leq 3500-200\\48n\leq 3200\\\text{Divide both sides by 48}\\n\leq66.7[/tex]

The delivery man can safely carry 66 Cartons.

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