Answer:
0.345 mol
Explanation:
We can solve this problem by using the equation of state for an ideal gas, which is
[tex]pV=nRT[/tex]
where
p is the pressure of the gas
V is its volume
n is the number of moles
R is the gas constant
T is the absolute temperature of the gas
For the oxygen in this problem we have:
V = 10.0 L is the volume
p = 0.844 atm is the pressure
[tex]R=0.082 atm\cdot L/(mol \cdot K)[/tex] is the gas constant
[tex]T=25.0C+273=298 K[/tex] is the absolute temperature of the gas
Solving for n, we find the number of moles:
[tex]n=\frac{pV}{RT}=\frac{(0.844)(10.0)}{(0.082)(298)}=0.345 mol[/tex]
