Answer:
[tex]pH=11.08[/tex]
Explanation:
Hello,
In this case, since calcium hydroxide a strong base, its dissociation will completely result in both calcium and hydroxyl ions:
[tex]Ca(OH)_2\rightarrow Ca^{2+}+OH^-[/tex]
Thus, the concentration of hydroxyl ions equals that of the calcium hydroxide, with which we could compute the pOH as shown below:
[tex]pOH=-log([OH^-]}=-log(0.0012)\\\\pOH=2.92[/tex]
Now, the pH and the pOH are related by:
[tex]pOH+pH=14[/tex]
Hence, the pH finally results:
[tex]pH=14-pOH=14-2.92\\pH=11.08[/tex]
Best regards.