Answer:
[tex]\Delta V=\frac{Q d}{A \epsilon_0}[/tex]
Explanation:
for the calculation of the electric potential inside a parallel plate capacitor you can use the formula for the electric field inside the capacitor.
[tex]\Delta V=V(d)-V(0)=\int_0^dEdx[/tex]
where d is the distance between plates and E is the electric field, which is given by:
[tex]E=\frac{\sigma}{\epsilon_0}[/tex]
By replacing you obtain:
[tex]\Delta V=E\int_0^ddx=Ed=\frac{\sigma d}{\epsilon_0}=\frac{Qd}{A\epsilon_0}[/tex]
where Q is the charge stored by the capacitor and A is the area of the plates.
hence, the answer is Qd/Ae0