Answer:
The diameter of the hole at 248.0 degrees Celsius is 1.330 cm.
Explanation:
given information
diameter, d₀ = 1.325 cm
initial temperature, T₁ = 21°
final temperature, T₂ = 248.0°
to calculate the diameter after the temperature increased
Δd = α d₀ ΔT
where
Δd = the change of diameter
α = thermal expansion constant
d₀ = initial diameter
ΔT = the change of temperature
thermal expansion constant for copper is 17 x 10⁻⁶/°C
thus,
Δd = α d₀ ΔT
= (17 x 10⁻⁶) (1.325) (248 - 21)
= 0.005 cm
so, the diameter of the hole at 248°C is
Δd = d - d₀
d = Δd + d₀
= 0.005 + 1.325
= 1.330 cm
