Answer:
The answer to your question is 6.54 g of H₂O
Explanation:
Data
mass of water = ?
mass of carbon dioxide = 16 g
Balanced chemical reaction
H₂CO₃ ⇒ H₂O + CO₂
Process
1.- Calculate the molar mass of the products
H₂O = (1 x 2) + (1 x 16) = 2 + 16 = 18 g
CO₂ = (1 x 12) + (16 x 2) = 12 + 32 = 44 g
2.- Use proportions and cross multiplication to solve this problem.
18 g of H₂O -------------------- 44 g of CO₂
x -------------------- 16 g of CO₂
x = (16 x 18) / 44
x = 288/44
x = 6.54 g of H₂O
