Answer:
23 and 16
Step-by-step explanation:
Answers
Let x be the number of peacocks and y be the number of buffalows.
Each Peacock has 2 eyes and 2 legs.
Each buffalow has 2 eyes and 4 legs.
Total no of eyes = 78
So 2x + 2y = 78......(1)
Total no of legs = 110
So 2x + 4y = 110......(2)
Substracting (1) and (2) we get,
2x + 4y = 110.
-2x + 2y = 78
2y = 32
y = 32/2
y = 16
Put y in equation 1
2x + 2y = 78
2x + 2*16 =78
2x + 32 = 78
2x = 78 - 32
2x = 46
x = 46/2
x = 23
x = 23 and y = 16
Answer: there were 16 buffalos and 23 peacocks.
Step-by-step explanation:
Let x represent the number of Buffaloes.
Let y represent the number of peacocks.
A Buffalo has 2 eyes while a peacock has 2 eyes. If the Buffalo and the peacock has 78 eyes in total, then
2x + 2y = 78
Dividing both sides of the equation by 2, it becomes
x + y = 39
x = 39 - y
A Buffalo has 4 legs while a peacock has 2 legs. If the Buffalo and the peacock has 110 in total, then
4x + 2y = 110- - - - - - - - - - - - 1
Substituting x = 39 - y into equation 1, it becomes
4(39 - y) + 2y = 110
156 - 4y + 2y = 110
- 4y + 2y = 110 - 156
- 2y = - 46
y = - 46/- 2
y = 23
x = 39 - y = 39 - 23
x = 16
