Answer: The volume of ethanolamine the student should pour out is [tex]9.80cm^3[/tex]
Explanation:
To calculate the volume of ethanolamine we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of ethanolamine = [tex]1.02g/cm^3[/tex]
Mass of ethanolamine = 10.0 g
Volume of ethanolamine = ?
Putting values in above equation, we get:
[tex]1.02g/cm^3=\frac{10.0g}{\text{Volume of ethanolamine}}\\\\{\text{Volume of ethanolamine}=\frac{10.0g}{1.02g/cm^3}=9.80cm^3[/tex]
Thus the volume of ethanolamine the student should pour out is [tex]9.80cm^3[/tex]
