Answer:
The bird's speed immediately after swallowing is 6.17 m/s.
Explanation:
Given that,
Mass of the bird, m = 270 g = 0.27 kg
Initial speed of the bird, u = 5 m/s
Mass of the insect, m' = 11 g = 0.011 kg
Initial speed of the insect, u' = 35 m/s
We need to find the bird's speed immediately after swallowing. Let it is given by V. Using the conservation of momentum as :
[tex]mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{0.27\times 5+0.011\times 35}{(0.27+0.011)}\\\\V=6.17\ m/s[/tex]
So, the bird's speed immediately after swallowing is 6.17 m/s.
