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Male-pattern baldness is a X-linked recessive trait, labelled X^{\text{b}}

b

start superscript, start text, b, end text, end superscript, with the dominant normal hair gene being X^{\text{B}}

B

start superscript, start text, B, end text, end superscript.

A father with the genotype X^{\text{B}}

B

start superscript, start text, B, end text, end superscriptY and a mother with the genotype X^{\text{b}}

b

start superscript, start text, b, end text, end superscriptX^{\text{b}}

b

start superscript, start text, b, end text, end superscript have a son.

What is the percent chance that the son will inherit male-pattern baldness?

Respuesta :

Oseni

Answer:

100%

Explanation:

Pattern baldness if X linked and recessive.

A father with [tex]X^BY[/tex] and a mother with [tex]X^bX^b[/tex] have a son.

First, let us look at the result of the cross between the two:

[tex]X^BY[/tex]   x   [tex]X^bX^b[/tex]

male progeny: [tex]X^bY, X^bY[/tex]

female progeny: [tex]X^BX^b, X^BX^b[/tex]

The two sons resulting from the cross inherited male pattern baldness. Hence, the percentage chance that the son will inherit male pattern baldness is 100.