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A father is three times old as his son. Six years ago, he was five times as old as his son. Find their current age​

Respuesta :

elfmagicteasjiskx

Answer:

The son is 12 years, and the father is 36 years.

Step-by-step explanation:

Define F as fathers age and S as sons age right now.

Then now they are

(1) 3S = F

and six years ago they were

(2) 5*(S-6) = F-6

calculate 5*(S-6)

5S - 30 = F-6

Subtract left and right side by -F

Add 30 to left and right side

5S - F = 24

Put (2) 3S = F into the equation above

5S - 3S = 24

2S = 24

S = 12

insert result in (2) 3S = F

3*12 = F

36 = F

So the son is 12 years, and the father is 36 years.

ayshaniyatp

Answer   :   son is 12 years, and the father is 36 years.

Step-by-step explanation  :   Define F as fathers age and S as sons age right now.

Then now they are

(1) 3S = F

and six years ago they were

(2) 5*(S-6) = F-6

calculate 5*(S-6)

5S - 30 = F-6

Subtract left and right side by -F

Add 30 to left and right side

5S - F = 24

Put (2) 3S = F into the equation above

5S - 3S = 24

2S = 24

S = 12

insert result in (2) 3S = F

3*12 = F

36 = F

So the son is 12 years, and the father is 36 years.

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