Answer:
False
Step-by-step explanation:
-We apply the Law of Sines to determine the two remaining sides:
[tex]\frac{a}{Sin \ A}=\frac{b}{Sin \ B}=\frac{c}{Sin \ C}\\\\\frac{16}{Sin \ 90\textdegree}=\frac{b}{Sin \ 30}, Sin \ 90\textdegree=1\\\\b=16Sin \ 30 \textdegree=8\\h=16Sin 60\textdegree=13.86[/tex]
#We use the calculated height and base dimensions to find it's area:
[tex]A=\frac{1}{2}bh\\\\=0.5\times 8\times 13.86\\\\=55.44\[/tex]
[tex]55.44\neq 64\sqrt{3}[/tex]
Hence, False(the calculated area is not equal to the stated area).
