Answer:
2 - 16i
Step-by-step explanation:
[tex](1 + 5i) \times ( - 3 - i) \\ = 1 \times ( - 3 - i) + 5i \times ( - 3 - i) \\ = - 3 - i - 15i - 5 {i}^{2} \\ = - 3 - 16i - 5( - 1)..( \because \: {i}^{2} = - 1) \\ - 3 - 16i + 5 \\ = 5 - 3 - 16i \\ = 2 - 16i \\ \purple{ \boxed{ \bold{ \therefore \: (1 + 5i) \times ( - 3 - i) = 2 - 16i }}} \\ [/tex]
