Answer:
.14L or 140mL
Explanation:
This is a classic plug-n-chug problem. Your textbook probably goes over this formula as [tex]M_{1}V_{1} = M_{2}V_{2}[/tex]. M stands for molarity of the given substance, and V stands for the volume that the substance occupies.
Simply plug in the values that you're given, like so:
[tex]M_{1} = 1.5M\\V_{1} = ???\\M_2 = 7M\\V_2 = .03L[/tex]
[tex]1.5M * x = 7M * .03L[/tex]
After completing the algebra portion and solving for the unknown, you will be left with x = .14L, which is the volume required to neutralize 30mL of 7M NaOH.
