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The label on a candy bar says 410 Calories. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. Part A Assuming a typical efficiency for energy use by the body, if a 60 kg person were to use the energy in this candy bar to climb stairs, how high could she go?

Respuesta :

amnamurad28748

Answer:

2.9174meters.

Explanation:

410Calories = 1715.44 Joules (Energy).

we have essentially calculate height at which Gravitational potential is 1715.44 Joules.

We know that Gravitational Potential as a function of height above reference point is.

[tex]G(h)=mgh[/tex].

Substituting values in gives.

[tex]1715.44 joules = 60Kg*9.8m/s^2*h[/tex]

in above solve for h and you will get.

h = 2.917meters (units are meters by dimentional analysis ).

That is the height a 60Kg person can reach by climbing stairs.

snehashish65

The person can climb up to the height of 2.91 m.

Given data:

The energy produced by candy is, [tex]E =410 \;\rm cal =410 \times 4.184 =1715.44 \;\rm J[/tex].

The mass of person is, m = 60 kg.

The given problem is based on energy conversion. Here, the candy bar is consumed by the person, for which the calories of energy will be converted into the potential energy of person.

Energy in Candy = Potential Energy

E = U

[tex]E =mgh[/tex]

Here, g is the gravitational acceleration and h is the height climbed by the person.

Solving as,

[tex]1715.44 = 60 \times 9.8 \times h\\\\h = \dfrac{1715.44}{60 \times 9.8} \\\\h =2.91 \;\rm m[/tex]

Thus, we can conclude that the person can climb up to the height of 2.91 m.

Learn more about the potential energy here:

https://brainly.com/question/24284560