Answer:
The heat transferred to the system is 1717.322 J
Explanation:
Given data:
n = moles of gas = 1 mol
T = temperature = 25°C = 298 K
Question: Calculate the heat transferred, Q = ?
[tex]\frac{V_{2} }{V_{1} } =2[/tex] (volume doubles due the gas expasion)
The heat transferred:
[tex]Q=nRTln(\frac{V_{2} }{V_{1} } )[/tex]
Here
R = ideal gas constant = 8.314 J/mol K
[tex]Q=1*8.314*298*ln(2)=1717.322J[/tex]
The heat transferred to the system is 1717.32 J
Let the initial volume (V₁) = v
Therefore,
The final volume (V₂) = 2v
From the question given above, the following data were obtained:
Q = nRTln(V₂/V₁)
Q = 1 × 8.314 ×298 × ln(2v/v)
Q = 2477.572 × ln2
Q = 1717.32 J
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