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To measure the speed of the jet stream, a weather plane left its base at noon and flew 800 km directly against the stream with an air speed of 750 km/h. It then returned directly to its base, arriving at 2:24 pm. What was the speed of the jet stream?

Respuesta :

Answer:

I’m not sure but I got this question asked before

Step-by-step explanation:

notyouagaincn

Answer:

250 km/h

Step-by-step explanation:

Let the speed of the jet stream be x and the time it took the jet to return to the base as y.

It took the plane 2 hours and 24 minutes for the journey.

The total hours into a fraction is 12/5 hours

The speed of the plane is 750km/h

So the speed against the jet stream is 750-x

The speed with the jet stream is 750+x

distance = time x speed

You can put an equation like this :

800/(750-x) + 800/(750+x)=12/5

800/(750-x) is the time that it took to travel 800km against jet stream

800/(750+x) is the time that it took to travel 800 km with the jet stream

Multiply the denominators with the least common multiple :

800(750+x)/(750-x)(750+x)+800(750-x)/(750-x)(750+x)=12/5

1200000=12/5(750-x)(750+x)

1200000=12/5(562500-x^2)

1200000=1250000-12/5(x^2)

12/5(x^2) = 150000

x^2 = 62500

x=250

Hope this helps even after 2 years XD

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