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If a car has a linear acceleration of 1.8m/s^2 and the radius of its wheels is 0.33m, what is the angular acceleration of the wheels? What was the angular displacement of the wheels after one minute?

Respuesta :

isaacoranseola

Answer:

5.45rad/s^2

Explanation: Given that

a = 1.8m/s^2

r = 0.33m

a= αr

1.8 = α × 0.33

1.8 = 0.33α

α = 1.8/0.33

α = 5.45rad/s^2

onyebuchinnaji

Answer:

The angular acceleration of the wheels is 5.46 rad/s²

The angular displacement of the wheels after one minute is 327.6 rad/s

Explanation:

Given;

linear acceleration, a = 1.8m/s²

radius of the wheel, r = 0.33m

The angular acceleration of the wheels is calculated as;

[tex]\alpha = \frac{a}{r}[/tex]

where;

[tex]\alpha[/tex] is angular acceleration

a is linear acceleration of the wheel

r is radius of the wheel

[tex]\alpha = \frac{1.8 }{0.33} =5.46 \ rad/s^2[/tex]

The angular displacement of the wheels after one minute;

ω = αt

Given;

time, t = 1 minutes = 60 seconds

ω = 5.46 x 60

ω = 327.6 rad/s

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