Answer : The correct option is, (C) 250 kPa
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
[tex]P\propto \frac{1}{V}[/tex]
or,
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1[/tex] = initial pressure = 124.6 kPa
[tex]P_2[/tex] = final pressure = ?
[tex]V_1[/tex] = initial volume = 1.50 L
[tex]V_2[/tex] = final volume = 0.75 L
Now put all the given values in the above equation, we get:
[tex]124.6kPa\times 1.50L=P_2\times 0.75L[/tex]
[tex]P_2=249.2kPa\approx 250kPa[/tex]
Thus, the pressure of helium need to experience to have a volume of 0.75 L would be, 250 kPa
