The first term of a geometric progression is 3 and the common ratio is 2 a)Write down the forth term of the progression b)write down the sixth term of the progression

Respuesta :

Answer:

a) Fourth term of the progression is 24

b) Sixth term of the progression is 96

Step-by-step explanation:

Formula for geometric sequence is,

[tex]a_{n}=ar^{n-1}[/tex]

where [tex]a_{n}=n^{th} term\:of\:sequence[/tex]

a = first term of sequence

r = common ratio

Given that first term of GP is 3. So, a = 3. Also common ratio is 2. So, r = 2.

a) To find fourth term of progression that is, [tex]a_{4}[/tex].

Substituting the values in given formula,

[tex]a_{4}=3\left(2^{4-1}\right)[/tex]

Simplifying,

[tex]a_{4}=3\left(2^{3}\right)[/tex]

[tex]a_{4}=3\left(8\right)[/tex]

[tex]a_{4}=24[/tex]

Therefore, the fourth term of progression is 24

b) To find sixth term of progression that is, [tex]a_{6}[/tex].

Substituting the values in given formula,

[tex]a_{6}=3\left(2^{6-1}\right)[/tex]

Simplifying,

[tex]a_{6}=3\left(2^{5}\right)[/tex]

[tex]a_{6}=3\left(32\right)[/tex]

[tex]a_{6}=96[/tex]

Therefore, the sixth term of progression is 96