A truck accelerates at 4.7 m/s for 150 m, reaching a final velocity of 47 m/s. What was it’s initial velocity?

Answer:
We can use option C
Initial velocity=28.3m/s
Explanation:
acceleration(a)=4.7m/s^2
distance(d)=150m
Final velocity(v)=47m/s
Initial velocity(u)=?
V^2=u^2+2xaxd
47^2=u^2+2x4.7x150
2209=u^2+1410
U^2=2209-1410
U^2=799
U=√(799)
u=28.3m/s