Maria invests $6,154 in a savings account with a fixed annual interest rate of 8% compounded continuously. What will the account balance be after 10 years?

Respuesta :

Answer:

$13,695.98

Step-by-step explanation:

Continuously compounded interest formula:

[tex] A = Pe^{rt} [/tex]

where

A = future value

P = principal (present value of amount invested)

e = mathematical constant, the base of natural logarithms

r = interest rate

t = time in years

We have: P = 6154; r = 8% = 0.08; t = 10

[tex] A = 6154e^{0.08 \times 10} [/tex]

[tex] A = 6154e^{0.8} [/tex]

[tex] A = 6154 \times 2.2255 [/tex]

[tex] A = 13695.98 [/tex]

Answer: $13,695.98