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Answer:
A (3,5), B (1,7) ,C(-1,-3),D(1,-5)
Explanation:
M[1,1]= [Diagonals bisect each other]
[tex][ \frac{x_{1} + x_{2}}{2} , \frac{y_{1} + y_{2}}{2}]\\(\frac{3+x_{2} }{2} , \frac{5+y_{2} }{2})\\\frac{3+x_{2} }{2}=1 , \frac{5+y_{2} }{2}=1\\3 + x_{2} = 2 , 5 + y_{2} = 2\\x_{2} = -1 , y_{2} = -3\\\\[/tex]
C(-1,-3)
M[1,1]= [Diagonals bisect each other]
[tex][\frac{x+1}{2} , \frac{y+7}{2}]\\\frac{x+1}{2}=1 , \frac{y+7}{2}=1\\x+1=2 , y+7=2\\x=1, y=-5[/tex]
D(1,-5)
hence,
A (3,5), B (1,7) ,C(-1,-3),D(1,-5)
