Step-by-step explanation:
[tex] {2x}^{2} + 4x - 5 = 0 \\ {2x}^{2} + 4x = 5 \\ \frac{ {2x}^{2} }{2} + \frac{4x}{2} = \frac{5}{2} \\ {x}^{2} + 2x = \frac{5}{2} \\ {x}^{2} + 2x + ( {\frac{2}{2} })^{2} = \frac{5}{2} + ( {\frac{2}{2} })^{2} \\ {x}^{2} + 2x + 1 = \frac{7}{2} \\ {(x + 1)}^{2} = + | - \frac{7}{2} \\ x + 1 = + | - \frac{ \sqrt{7} }{ \sqrt{2} } [/tex]
