Answer:
A. I only
Step-by-step explanation:
We need to start off by taking perfect squares out of these square roots.
Begin with the numerator. It looks like we can take 4 out of the radical:[tex]\sqrt{40} = \sqrt{4*10} = \sqrt{4} * \sqrt{10} = 2 \sqrt{10}[/tex]
Now we have
[tex]\frac{2\sqrt{10}}{\sqrt{10} }[/tex]
Looks like those [tex]\sqrt{10}[/tex]s can cancel!
= 2
Plug those answers into your calculator. II and III don't equal 2, but I does. This makes sense when we consider the rule that if you're dividing two radicals, you can just pull the radical over the whole expression!
The answer is A. I only.
