Respuesta :
Hello,
[tex]4^{12-4x}=256\\ ==\ \textgreater \ \ 2^{24-8x}=2^8\\ ==\ \textgreater \ \ 24-8x=8\\ ==\ \textgreater \ 8x=16\\ ==\ \textgreater \ x=2[/tex]
[tex]4^{12-4x}=256\\ ==\ \textgreater \ \ 2^{24-8x}=2^8\\ ==\ \textgreater \ \ 24-8x=8\\ ==\ \textgreater \ 8x=16\\ ==\ \textgreater \ x=2[/tex]
Hi
4^(12-4x) =256
First we need to take log of both sides
log(4^-4x+12) = log (256)
(-4x + 12)(log(4)) = log(256)
so now we have
-4x + 12 = log(256)/log(4)
-4x + 12 = 4
-4x = 4 - 12
-4x = -8
x = -8/-4
x= 2
I hope that's help :)
4^(12-4x) =256
First we need to take log of both sides
log(4^-4x+12) = log (256)
(-4x + 12)(log(4)) = log(256)
so now we have
-4x + 12 = log(256)/log(4)
-4x + 12 = 4
-4x = 4 - 12
-4x = -8
x = -8/-4
x= 2
I hope that's help :)