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line J passes through points (-6,1) and (-3,6) . Line m is parallel to line j and passes through point (15,-1).what is the equation of line m ?

Respuesta :

Kunchan
slope of the line J
(6-1) / (-3-(-6))
5 / 3

so
m = 5/3

If this line passes through (15,-1)
y = mx + c
-1 = (5/3)*15 + c
-1 = 25 + c
c = -26

equation is
y = (5/3)x - 26

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