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Consider the reaction 2X2Y+Z2⇌2X2YZ which has a rate law of rate= k[X2Y][Z2] Select a possible mechanism for the reaction. View Available Hint(s) Consider the reaction which has a rate law of Select a possible mechanism for the reaction. A Step1:Step2:Step3:Z2→Z+Z (slow)X2Y+Z→X2YZ (fast) X2Y+Z→X2YZ (fast) B Step1:Step2:X2Y+Z2→X2YZ+Z (slow)X2Y+Z→X2YZ (fast) C Step1:Step2:X2Y+Z2→X2YZ2 (slow)X2YZ2→X2YZ+Z (fast) D Step1:Step2:2X2Y⇌X4Y2 (fast)X4Y2+Z2→2X2YZ (slow) E Step1:2X2Y+Z2→2X2YZ (slow)

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Answer:

Check the explanation

Explanation:

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We can conclude that Slow step is the rate determining step. A further explanation or mechanism is provided below.

Chemical reaction:

A mechanism that converts one or maybe more compounds, also known as reactants, around one or maybe more distinct compounds or chemicals, described as products.

Whenever a material undergoes a physical transformation, its physical attributes change, although its chemical identification remains unchanged.

According to the question,

Reaction is: 2X₂Y+Z₂⇌2X₂YZ

Rate law: k[X₂Y][Z₂]

The mechanism will be:

First step:

The slower one i.e.,

→ X₂Y + Z₂ [tex]\rightarrow[/tex] X₂YZ + Z

Second step:

The faster one i.e.,

→ X₂Y + Z [tex]\rightarrow[/tex] X₂YZ

Thus the slow step is rate determining step of the above response is appropriate.

Find out more information about reaction here:

https://brainly.com/question/26018275

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