Respuesta :
Answer:
A(1) = 1000
A(2) = A(1) - A(1) x 10/100 + 40
A(3) = A(2) - A(2) x 10/100 + 40
=> A(n) = A(n-1) - A(n-1) x 10/100 + 40
Hope this helps!
:)
Answer:
An = 0.9A(n-1) + 40
Step-by-step explanation:
10% decrease means 100-10 = 90% of the previous
A1: 1000
A2: (90% of 1000) + 40 = 0.9(1000) + 40
A3: 0.9(0.9(1000) + 40) + 40
= 0.9²(1000) + 0.9(40) + 40
A4: 0.9(0.9²(1000) + 0.9(40) + 40) + 40
An = 0.9A(n-1) + 40