9514 1404 393
Answer:
(c) ∛(2x) -6∛x
Step-by-step explanation:
The expression is simplified by removing the cubes from under the radical and combining like terms.
[tex]7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}\\\\=7\sqrt[3]{2x}-3\sqrt[3]{2^3\cdot2x}-3\sqrt[3]{2^3x}\\\\=7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}\\\\=\boxed{\sqrt[3]{2x}-6\sqrt[3]{x}}\qquad\text{matches 3$^\text{rd}$ choice}[/tex]
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Comment on the question
Both the question and answer choices would be much easier to identify if the usual math symbols were used, along with appropriate formatting.
