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A 0.05 kg tennis ball moves at a speed of 10 m/s and is struck by a racket causing it to rebound in the
opposite direction at a speed 16 m/s. What is the impulse exerted on the ball?

Respuesta :

F=ma
F=m[(v-u)/t]
Ft=m[v-u]
Ft=mv-mu
Ft=(0.05x10)-(0.05x16)
Ft= -0.3 Ns
Impulse= -0.3 Ns.

The impulse exerted on the tennis ball is 0.3N.

To, determine the impulse exerted on the ball, we need to know about impulse.

What is impulse?

It is a resultant force that causes acceleration and a change in velocity of the body for as long as it acts.

What is the mathematical formulation of impulse?

Mathematically, impulse is the change in momentum of an object.

       so, impulse= final momentum - initial momentum

Here, initial momentum of the ball= mass × initial velocity

                                                        = 0.05 × 10 = 0.5 Kg m/s

       Final momentum of the ball= mass × final velocity

                                                     = 0.05 × 16= 0.8 Kg m/s

So, impulse exerted on the ball = 0.8 - 0.5 = 0.3 Kg m/s

Thus, we can conclude that the impulse exerted on the ball is 0.3 Kg m/s.

Learn more about impulse here:

https://brainly.com/question/904448

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