Respuesta :

mathstudent55

Answer:

See below.

Step-by-step explanation:

Using a calculator, find sqrt(2). You get:

[tex] \sqrt{2} = 1.4142 [/tex]

Now to find

[tex] \sqrt{2} + \sqrt{2} + \sqrt{2} = [/tex]

add

1.4142 + 1.4142 + 1.4142 to get 4.2426

The actual sum of

[tex] \sqrt{2} + \sqrt{2} + \sqrt{2} [/tex]    equals approximately 4.2426

Now let's see what sqrt(6) is equal to.

Use a calculator again, and find sqrt(6).

[tex] \sqrt{6} = 2.4495 [/tex]

As you can see, the correct sum, 4.2426, is very different from 2.4495, so sqrt(6) is not equal to the sum [tex] \sqrt{2} + \sqrt{2} + \sqrt{2} [/tex].

judygachanja

Answer:

yes they are equal.

Step-by-step explanation:

instead of saying; squareroot 2 + sq2+ sq2 , it is more logic add the numbers and square root them once.

so, if you add them you will get 6 , which you will square root after.

NOTE that this only applies when you have same number inside the root sign.

hope you will understand.

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