Answer:
a) CH4 (g) (1 mole) + H2O (g) (1 mole) = CO (g) + 3H2 (g) (3 moles).
b) 3/1 or 3 will be the conversion factor used to convert moles of methane and the moles of hydrogen.
c) Based on the given mole-mole relation,
The number of moles of hydrogen produced by 1 mole of CH4 or methane is 3 moles. Therefore, the number of moles of hydrogen produced from 7 moles of CH4 would be,
3/1 * 7 = 21 moles.
d) The formation of 3 moles of hydrogen is taking place from 1 mole of water vapor or H2O. Therefore, the number of moles of water vapor required to produced 100.50 moles of hydrogen would be,
1/3 * 100.50 moles = 33.5 moles.